(3x-7)(5x+6)=15x^2

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Solution for (3x-7)(5x+6)=15x^2 equation: 



(3x-7)(5x+6)=15x^2

We move all terms to the left:

(3x-7)(5x+6)-(15x^2)=0

determiningTheFunctionDomain
-15x^2+(3x-7)(5x+6)=0

We multiply parentheses ..

-15x^2+(+15x^2+18x-35x-42)=0

We get rid of parentheses

-15x^2+15x^2+18x-35x-42=0

We add all the numbers together, and all the variables

-17x-42=0

We move all terms containing x to the left, all other terms to the right

-17x=42

x=42/-17

x=-2+8/17

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